Question 8 of 32intermediate🔧 ApplyShort Answer3 marks

Write structures and IUPAC names of different structural isomers of alkenes corresponding to C₅H₁₀.

Correct Answer

The different structural isomers of alkenes corresponding to C5H10C_5H_{10} and their IUPAC names are:

(a) CH2=CH−CH2−CH2−CH3\text{CH}_2 = \text{CH} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 Pent-1-ene

(b) CH3−CH=CH−CH2−CH3\text{CH}_3 - \text{CH}=\text{CH} - \text{CH}_2 - \text{CH}_3 Pent-2-ene

(c) CH3−C=CH−CH3\text{CH}_3 - \text{C} = \text{CH} - \text{CH}_3 (with a CH3\text{CH}_3 group attached to the second carbon) 2-Methylbut-2-ene

(d) CH3−CH−CH=CH2\text{CH}_3 - \text{CH} - \text{CH} = \text{CH}_2 (with a CH3\text{CH}_3 group attached to the third carbon) 3-Methylbut-1-ene

(e) CH2=C−CH2−CH3\text{CH}_2 = \text{C} - \text{CH}_2 - \text{CH}_3 (with a CH3\text{CH}_3 group attached to the second carbon) 2-Methylbut-1-ene

Exercise: Problem 9.9 | Q: 9.9 | (Page Page 14)
For More Understanding

Explanation

The molecular formula C5H10C_5H_{10} corresponds to an alkene. By varying the position of the double bond and the branching of the carbon chain, five distinct structural isomers can be formed. These include straight-chain pentenes (pent-1-ene and pent-2-ene) and branched-chain methylbutenes (2-methylbut-2-ene, 3-methylbut-1-ene, and 2-methylbut-1-ene).

Solution Steps

  1. Step 1: Identify the straight-chain isomers by moving the double bond: Pent-1-ene and Pent-2-ene.

  2. Step 2: Identify the branched-chain isomers using a four-carbon main chain and a methyl substituent: 2-Methylbut-2-ene, 3-Methylbut-1-ene, and 2-Methylbut-1-ene.

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