Question 13 of 32intermediate💡 UnderstandShort Answer2 marks

How do you account for the formation of ethane during chlorination of methane?

Correct Answer

The chlorination of methane proceeds via a free radical chain mechanism involving initiation, propagation, and termination steps. During the propagation step, chlorine free radicals attack methane to generate methyl free radicals (H3C˙\text{H}_3 \dot{\text{C}}).

In the chain terminating step, these highly reactive methyl free radicals can combine with each other. When two methyl free radicals react, they form a C-C bond, resulting in the formation of ethane (H3C−CH3\text{H}_3\text{C} - \text{CH}_3).

The reaction is: H3C˙+CH˙3→H3C−CH3\text{H}_3 \dot{\text{C}} + \dot{\text{CH}}_3 \rightarrow \text{H}_3\text{C} - \text{CH}_3. This accounts for the formation of ethane as a byproduct during the chlorination of methane.

Exercise: EXERCISES | Q: 9.1 | (Page Page 33)
For More Understanding

Explanation

The textbook context explains that halogenation of alkanes proceeds via a free radical chain mechanism. The formation of ethane occurs during the chain terminating step of this mechanism, where two methyl free radicals combine.

Solution Steps

  1. Step 1: Identify that chlorination of methane is a free radical chain mechanism.

  2. Step 2: Note that methyl free radicals (H3C˙\text{H}_3 \dot{\text{C}}) are generated during the propagation step.

  3. Step 3: Explain that in the chain terminating step, two methyl free radicals combine to form ethane: H3C˙+CH˙3→H3C−CH3\text{H}_3 \dot{\text{C}} + \dot{\text{CH}}_3 \rightarrow \text{H}_3\text{C} - \text{CH}_3.