Arrange benzene, n-hexane and ethyne in decreasing order of acidic behaviour. Also give reason for this behaviour.
The decreasing order of acidic behaviour is: Ethyne > Benzene > n-hexane.
Reason: The acidic behaviour of hydrocarbons is determined by the hybridisation of the carbon atom bonded to the hydrogen. Ethyne has sp hybridised carbons (50% s-character), benzene has sp2 hybridised carbons (33.3% s-character), and n-hexane has sp3 hybridised carbons (25% s-character). Since s-electrons are closer to the nucleus, a higher percentage of s-character increases the electronegativity of the carbon atom. This makes the C-H bond more polar and the conjugate base more stable, thereby increasing the acidic character. As alkanes, alkenes, and alkynes follow the trend , ethyne is the most acidic, followed by the aromatic benzene, and finally the alkane n-hexane.
Explanation
The textbook context highlights that alkynes like ethyne show acidic behaviour by reacting with active metals like sodium to form ethynides, a reaction not shown by alkanes and alkenes. The trend is given. To place benzene, we apply the concept of hybridisation: ethyne (sp) is more acidic than benzene (sp2), which is more acidic than n-hexane (sp3) due to the decreasing percentage of s-character.
Solution Steps
Step 1: Identify the hybridisation of the carbon atoms in each compound. Ethyne is sp hybridised, benzene is sp2 hybridised, and n-hexane is sp3 hybridised.
Step 2: Relate hybridisation to s-character. sp has 50% s-character, sp2 has 33.3%, and sp3 has 25%.
Step 3: Conclude that higher s-character leads to greater electronegativity of the carbon atom, making the hydrogen more easily lost as a proton (more acidic). Thus, the order is Ethyne > Benzene > n-hexane.