Option (D) is incorrect. The context explains that the penetration of a 2s-electron to the nucleus is more than that of a 2p-electron, meaning the 2s electron is attracted more strongly to the nucleus. Therefore, it is easier to remove a 2p-electron (higher n value or less penetrating) compared to a 2s-electron (lower n value or more penetrating). This contradicts statement (D), which claims removal from orbitals bearing a lower n value is easier.