Question 9 of 48beginner🔧 ApplyShort Answer2 marks

Show by a chemical reaction with water that Na₂O is a basic oxide and Cl₂O₇ is an acidic oxide.

Correct Answer

Na2ONa_2O is a basic oxide because it reacts with water to form a strong base, sodium hydroxide (NaOHNaOH). The chemical reaction is:

Na2O+H2O→2NaOHNa_2O + H_2O \rightarrow 2NaOH

In contrast, Cl2O7Cl_2O_7 is an acidic oxide because it reacts with water to form a strong acid, perchloric acid (HClO4HClO_4). The chemical reaction is:

Cl2O7+H2O→2HClO4Cl_2O_7 + H_2O \rightarrow 2HClO_4

The basic or acidic nature of these resulting solutions can be qualitatively tested with litmus paper. Elements on the extreme left of the period form the most basic oxides, while elements on the extreme right form the most acidic oxides.

Exercise: IN-TEXT QUESTIONS (PROBLEMS) | Q: Problem 3.10 | (Page 21)
For More Understanding

Explanation

The textbook context explicitly provides the reactions of Na2O and Cl2O7 with water. Na2O forms NaOH (a strong base), proving it is a basic oxide. Cl2O7 forms HClO4 (a strong acid), proving it is an acidic oxide. The context also mentions that their nature can be tested with litmus paper and relates this to the position of the elements in the periodic table (extreme left vs extreme right).

Solution Steps

  1. Step 1: Write the reaction of Na2ONa_2O with water to show it forms a strong base: Na2O+H2O→2NaOHNa_2O + H_2O \rightarrow 2NaOH.

  2. Step 2: Write the reaction of Cl2O7Cl_2O_7 with water to show it forms a strong acid: Cl2O7+H2O→2HClO4Cl_2O_7 + H_2O \rightarrow 2HClO_4.

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