A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
Given: Power of lens, P = +1.5 D
To find: Focal length of the lens and its nature.
Formula: P = 1/f
Calculation: f = 1/P = 1/(+1.5) = +0.67 m (or +66.7 cm)
Nature of lens: The power of the prescribed lens is positive (+1.5 D). According to the text, the power of a convex lens is positive and that of a concave lens is negative. A convex lens converges light rays. Therefore, the prescribed lens is converging.
Explanation
This is a straightforward application of the power-focal length relationship. The formula P = 1/f is given in the textbook context. Since power is positive, the focal length must also be positive, indicating a convex lens. The context explicitly states that 'the power of a convex lens is positive' and convex lenses are converging lenses that focus light rays closer to the optical centre.
Solution Steps
Step 1: Write the given value: Power P = +1.5 D
Step 2: Apply the formula P = 1/f, rearranged as f = 1/P
Step 3: Calculate: f = 1/(+1.5) = +0.67 m
Step 4: Identify lens type: Since power is positive, it is a convex lens
Step 5: Conclude: Convex lens is a converging lens