Question 19 of 21intermediate🔧 ApplyNumerical3 marks

To find out the concentration of SO₂ in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:

Concentration of SO₂ (in ppm)Frequency
0.00 - 0.044
0.04 - 0.089
0.08 - 0.129
0.12 - 0.162
0.16 - 0.204
0.20 - 0.242

Find the mean concentration of SO₂ in the air.

Correct Answer

To find the mean concentration, we use the Direct Method. First, we calculate the class mark (xix_i) for each class interval by averaging the upper and lower limits. Then, we find the product of frequency and class mark (fixif_i x_i) for each class.

The calculations are shown in the table below:

Concentration of SO₂ (ppm)Frequency (fif_i)Class Mark (xix_i)fixif_i x_i
0.00 - 0.0440.020.08
0.04 - 0.0890.060.54
0.08 - 0.1290.100.90
0.12 - 0.1620.140.28
0.16 - 0.2040.180.72
0.20 - 0.2420.220.44
TotalΣfi=30\Sigma f_i = 30Σfixi=2.96\Sigma f_i x_i = 2.96

Using the formula xˉ=ΣfixiΣfi\bar{x} = \frac{\Sigma f_i x_i}{\Sigma f_i}, we substitute the values: xˉ=2.9630=0.099\bar{x} = \frac{2.96}{30} = 0.099. Therefore, the mean concentration of SO₂ in the air is 0.099 ppm.

Exercise: EXERCISE 13.1 | Q: 7 | (Chapter: 12)
For More Understanding

Explanation

The solution follows the Direct Method for grouped data as illustrated in the provided context (Table 13.3). The context explains that for grouped data, we find the class mark (xix_i) for each interval, multiply it by the frequency (fif_i), and sum these products (Σfixi\Sigma f_i x_i). The mean is then calculated by dividing this sum by the total frequency (Σfi\Sigma f_i).

Solution Steps

  1. Step 1: Calculate class marks (xix_i) for each interval using the formula xi=Upper Limit+Lower Limit2x_i = \frac{\text{Upper Limit} + \text{Lower Limit}}{2}.

  2. Step 2: Calculate the product fixif_i x_i for each class interval.

  3. Step 3: Sum the frequencies to get Σfi=30\Sigma f_i = 30 and sum the products to get Σfixi=2.96\Sigma f_i x_i = 2.96.

  4. Step 4: Apply the mean formula xˉ=ΣfixiΣfi=2.9630=0.099\bar{x} = \frac{\Sigma f_i x_i}{\Sigma f_i} = \frac{2.96}{30} = 0.099.