6 children sit in the bus at the first stop. At the second stop, 8 more children board the bus. 7 children get down at the third bus stop. How many children are there in the bus at the third stop?
Given: 6 children at first stop 8 more children board at second stop 7 children get down at third stop
Calculation: Step 1: Children after second stop = 6 + 8 = 14 children Step 2: Children after third stop = 14 - 7 = 7 children
Answer: There are 7 children in the bus at the third stop.
Explanation
This is a two-step problem. First, add the children who boarded: 6 + 8 = 14 children. Then subtract the children who got down: 14 - 7 = 7 children remain.
Solution Steps
Step 1: 6 children sit in the bus at first stop
Step 2: At second stop, 8 more children board: 6 + 8 = 14 children
Step 3: At third stop, 7 children get down: 14 - 7 = 7 children
Step 4: 7 children remain in the bus