Who am I?
I am between 5 and 10. I become three more when read upside down.
The number is 6. When read upside down, 6 becomes 9, which is three more than 6.
I am 3 more than 8 and 3 less than 14.
The number is 11. It is 3 more than 8 (8+3=11) and 3 less than 14 (14-3=11).
I am after 50 and before 54. Sum of my digits is 7.
The number is 52. It comes after 50 and before 54. The sum of digits is 5+2=7.
I am just before 40.
The number is 39. The number just before 40 is 39.
Add 5 to me and you will get 24.
The number is 19. Adding 5 to 19 gives 24 (19+5=24).
I am just after 35.
The number is 36. The number just after 35 is 36.
Reduce 8 from me and 14 will be left.
The number is 22. Reducing 8 from 22 leaves 14 (22-8=14).
Explanation
(i) Numbers between 5 and 10 are 6, 7, 8, 9. When 6 is turned upside down, it looks like 9. The difference between 9 and 6 is 3. (ii) Adding 3 to 8 gives 11. Subtracting 3 from 14 also gives 11. Both conditions are satisfied. (iii) Numbers after 50 and before 54 are 51, 52, 53. Only 52 has digits that sum to 7 (5+2=7). (iv) The number immediately before 40 in the counting sequence is 39. (v) To find the number, subtract 5 from 24: 24-5=19. (vi) The number immediately after 35 in the counting sequence is 36. (vii) To find the number, add 8 to 14: 14+8=22.